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2024年3月7日发(作者：嵌入式开发分为哪些)

df1:

id fname0 1 Kate1 2 John2 5 Elidf2: age grade0 10 A1 20 B2 50 Cdf3: id age0 3 301 4 40df1_append_df2: id fname age grade0 1.0 Kate NaN NaN1 2.0 John NaN NaN2 5.0 Eli NaN NaN0 NaN NaN 10.0 A1 NaN NaN 20.0 B2 NaN NaN 50.0 Cdf1_append_df2_df3: id fname age grade0 1.0 Kate NaN NaN1 2.0 John NaN NaN2 5.0 Eli NaN NaN3 NaN NaN 10.0 A4 NaN NaN 20.0 B5 NaN NaN 50.0 C6 3.0 NaN 30.0 NaN7 4.0 NaN 40.0 NaN追加 Series

df1: id fname0 1 Kate1 2 John2 5 Elis1:a aab bbdtype: objects2:id 110fname Supermendtype: objectdf1_appened_s1: id fname a b0 1.0 Kate NaN NaN1 2.0 John NaN NaN2 5.0 Eli NaN NaN3 NaN NaN aa bbdf1_appened_s2: id fname0 1 Kate1 2 John2 5 Eli3 110 Supermen追加 dict 字典代码：

import pandas as pdidnumber = [1,2,5]fname = ['Kate','John','Eli']df1 = ame({'id':idnumber,'fname':fname})dicts_1 =[{"a":"aa", "b":"bb"},{"a":"aaa", "b":"bbb"}]dicts_2 =[{"id":"110", "fname":"Supermen"},{"id":"111", "fname":"Superwoman"}]print("df1:n{}".format(df1))print("dicts_1:n{}".format(dicts_1))print("dicts_1:n{}".format(dicts_1))df1_appened_dicts_1 = (dicts_1)df1_appened_dicts_2 = (dicts_2, ignore_index=True)print("df1_appened_dicts_1:n{}".format(df1_appened_dicts_1))print("df1_appened_dicts_2:n{}".format(df1_appened_dicts_2))输出：df1: id fname0 1 Kate1 2 John2 5 Elidicts_1:[{'a': 'aa', 'b': 'bb'}, {'a': 'aaa', 'b': 'bbb'}]dicts_1:[{'a': 'aa', 'b': 'bb'}, {'a': 'aaa', 'b': 'bbb'}]df1_appened_dicts_1: id fname a b0 1.0 Kate NaN NaN1 2.0 John NaN NaN2 5.0 Eli NaN NaN0 NaN NaN aa bb1 NaN NaN aaa bbbdf1_appened_dicts_2: id fname0 1 Kate1 2 John2 5 Eli3 110 Supermen4 111 Superwoman


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