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(s⇒t)
logic - ¬q, (¬p⇒(¬q⇒¬r)), (s∨r), (s⇒t), and (p⇒t), prove t., using Fitch - Stack Overflow
I am doing an intro to logic course and have been set the above. The rules allowed are:and introduction
logic172q
(172p⇒(172q⇒172r))
(s∨r)
(s⇒t)
and (p⇒t)
admin
12天前
12
0