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I have to do jQuery form validation for password.

The password should contain at least two special characters in any order. I have tried with Regular Expression for password validation but it does not address that two random special characters can e at any order.

How do I do it using a JavaScript regular expression?

I have to do jQuery form validation for password.

The password should contain at least two special characters in any order. I have tried with Regular Expression for password validation but it does not address that two random special characters can e at any order.

How do I do it using a JavaScript regular expression?

  • javascript
  • regex
  • validation
  • passwords
Share Improve this question edited May 23, 2017 at 11:51 CommunityBot 11 silver badge asked Jun 4, 2015 at 15:59 Nasif Md. TanjimNasif Md. Tanjim 3,9825 gold badges29 silver badges40 bronze badges 1
  • At least two special characters and at least one numeric character: /^(?=.*\d)(?=(.*[`!@#$%\^&*\-_=\+'/\.,]){2})(?!.*\s).{6,15}$/ – Nasif Md. Tanjim Commented Jun 4, 2015 at 18:05
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3 Answers 3

Reset to default 6

You do not have to use look-arounds in cases when you do not have to.

If you only need to make sure the string has at least 2 characters of a specific set, use this kind of a regex (with a negated class to make it more robust):

/(?:[^`!@#$%^&*\-_=+'\/.,]*[`!@#$%^&*\-_=+'\/.,]){2}/

See demo

In javascript it worked for me:

/(?=(.*[`!@#$%\^&*\-_=\+'/\.,]){2})/

var goodtogo = false;
var pass = 'simp!le@';   //example
var times = pass.match(/[\\\[\]\/\(\)\+\*\?`!@#$%\^&_=-]/g).length;
if(times >= 2)
    goodtogo = true;

Now I advice you to try several passwords and if you find a bug or something don't hesitate to yell back.

And if you have more special chars just add them to the parameter for match.

Hope it helps.

本文标签： javascriptRegular expression to match at least two special characters in any orderStack Overflow

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