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C4996 ‘scanf‘: This function or variable may be unsafe. Consider using scanf_s instead. To disable

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更新时间：2025-04-22 04:16:47 3

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大家在使用vs2022时会用到scanf函数，第一次使用时会遇到一些问题这里主要是给大家提供一些解决方法
C4996 ‘scanf’: This function or variable may be unsafe. Consider using scanf_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS. See online help for details.

这里在使用scanf函数时，会报出错误提示scanf函数不安全，如何解决呢？
1.可以使用scanf_s函数，但是这种方法我不建议，因为你的代码使用了scanf_s函数，其他编译器就不认识，代码可移植性就不好了
2.在源文件（.c）第一行加上#define #define _CRT_SECURE_NO_WARNINGS，但是每次都要这样是不是很麻烦？这里给大家提供一个一劳永逸的方法，也是我最推荐的方法！
在文件中找到newc++file.cpp这个文件

打开这个文件把上面的一句代码写到这个文件中，即可在每次创建文件时自动加入此句话，也就彻底解决了这个问题
在查找文件的时候可以使用everything，速度非常快
有的电脑会提示无法保存，只要复制一份文件放在桌面再写入，然后替换原位置文件即可！！！

本文标签： function scanf variable Disable scanfs

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